Question

a drum of mass 'm' kg was rolled down a ramp . at the bottom of the ramp of the kinetic energy was 10 kJ and velocity was 20 m/s with velocity in m/s was it pushed down the ramp if its initial kinetic energy was 625J

Answer 1

Answer:

5m/s

Explanation:

use the formula K.E=0.5*m*v^2

first find the m by this formula. m is 50kg.

Then use this m to find the v when K.E is 625J.