Question

A drunk is walking along a straight load it X5 a step forward and three step backward and so on each step is 1 metre long and take one second there is a bit on the road 11 metre always from the starting point the drunkard will fall into the pit after

Answer 1

consider 5 step forward and 3 step backward as 1 process.
i.e when he completed 1 process he only covered 2 steps.
time taken for 1 step=1 sec
therefore, when he completed one process he takes 8 sec.

1 step=1m
such that when he cpmple three process and 5 steps foward he will fall into pit
i.e the time taken is (8×3)+5=24+5=29 sec

hope,this ans is right

Answer 2

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Distance covered with 1 step = 1 m

Time taken = 1 s

Time taken to move first 5 m forward = 5 s

Time taken to move 3 m backward = 3 s

Net distance covered = 5 – 3 = 2 m

Net time taken to cover 2 m = 8 s

Drunkard covers 2 m in 8 s.

Drunkard covered 4 m in 16 s.

Drunkard covered 6 m in 24 s.

Drunkard covered 8 m in 32 s.

In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.

Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s

I hope, this will help you

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