Question

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward, followed by 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 second. There is a pit on road 11 m away from the starting point. The drunkard will fall into the pit after how many seconds?

Answer 1

For 8 total steps it takes 8 seconds, and moves in total 2 steps forward (2 m)

Therefore, 3*2 m = 6 m At 3rd cycle

Time Elapsed 24 s

After walking 5 m forward, he takes 5s more. It becomes 11 m.

Time = 24 + 5 = 29m