Question

a drunkard is walking along a straight road he takes 5 steps forward and three steps backward and so on .each step is is 1 m long and takes 1 second. there is a pit on the road 11 metre away from the starting point. the drunkard will fall into the pit after how much time? ​

Answer 1

Answer:

Explanation:

So the steps he makes forward is 5 and the steps he takes back is 2

And each step is 1m long and takes 1 second

Hence 5 steps in 5 secs= 5mtrs

And 3 steps in 3 secs= 3mtrs

So totally he goes 5-3+5-3+5-3+5=11

So total time will be 5+3+5+3+5+3+5=29 seconds

Because he takes 1 sec for each step whether forward or backward

Answer 2

✔️ Answer ✔️

Your answer:-

He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position

x= 5-3=2m in 8 sec

after 24sec he will 6m away from an initial position

He moves further 5m forward then he falls in a pit which is 11m away from the initial position.

total time T=24+5=29sec.

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