Math, asked by varshask26, 11 months ago


A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1ft long. There is a pit on the road 15 ft away from the starting point. The drunkard will fall into the pit after how many steps?

Answers

Answered by anjnamahe
1

Answer:

Hey dear your answer is 45. After 45 steps he would fall into the pit.

Hope it helps you

Answered by Anonymous
5

✔️ Answer ✔️

Your answer:-

Answer

He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position

x= 5-3=2m in 8 sec

after 24sec he will 6m away from an initial position

He moves further 5m forward then he falls in a pit which is 11m away from the initial position.

total time T=24+5=29sec.

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