A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1ft long. There is a pit on the road 15 ft away from the starting point. The drunkard will fall into the pit after how many steps?
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Answer:
Hey dear your answer is 45. After 45 steps he would fall into the pit.
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He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position
x= 5-3=2m in 8 sec
after 24sec he will 6m away from an initial position
He moves further 5m forward then he falls in a pit which is 11m away from the initial position.
total time T=24+5=29sec.
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