A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward, followed by 5 steps forward and 3 steps backward and so on. Each step is one meter long and takes one second. There is a pit on the road 11 meter away from the starting point then after how much time drunkard will fall into the pit?
Answers
Answered by
1
Answer:
11 meters it would take him 44 sec.
Explanation:
In 8 sec. he moves 2 meters ahead.
:- 1 meters in 4 sec.
thus, for 11 meters it would take him 4 x 11 secs = 44 sec.
Answered by
8
✔️ Answer ✔️
Your answer:-
He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position
x= 5-3=2m in 8 sec
after 24sec he will 6m away from an initial position
He moves further 5m forward then he falls in a pit which is 11m away from the initial position.
total time T=24+5=29sec.
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