A drunkard is walking along a straight road
He takes 5 steps forward and 3 steps backward
and so on. Each step is Im long and takes Is.
There is a pit on the road 1lm away from the
starting point. The drunkard will fall into the
pit after
Pls guys help
Answers
Answered by
3
Answer:
He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position
x= 5-3=2m in 8 sec
after 24sec he will 6m away from an initial position
He moves further 5m forward then he falls in a pit which is 11m away from the initial position.
total time T=24+5=29sec.
Hence the option B is correct.
Answered by
2
Answer:
He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position
x= 5-3=2m in 8 sec
after 24sec he will 6m away from an initial position
He moves further 5m forward then he falls in a pit which is 11m away from the initial position.
total time T=24+5=29sec.
Explanation:
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