A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward, followed by 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes 1 second. There is a pit on road 11 m away from the starting point. The drunkard will fall into the pit after how many seconds?
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He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position
x= 5-3=2m in 8 sec
after 24sec he will 6m away from an initial position
He moves further 5m forward then he falls in a pit which is 11m away from the initial position.
total time T=24+5=29sec.
Hence the option B is correct.
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