Question

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward,
followed by 5 steps forward and 3 steps backward and so on. Each step is 1 m long and takes
1 second. There is a pit on the road 11 m away from the starting point. The drunkard will fall info
the pit after
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Answer 1

Answer: 29 sec is right

Explanation:

He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position  

x= 5-3=2m  in 8 sec

after 24sec he will 6m away from an initial position

He moves further 5m forward then he falls in a pit which is 11m away from the initial position.

total time T=24+5=29sec.