A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s.There is pit on the road 11m away from the starting point. The drunkard will fall into the pit after what time.
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Answered by
2
Answer:
29 s
Explanation:
He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position
x= 5-3=2m in 8 sec
after 24sec he will 6m away from an initial position
He moves further 5m forward then he falls in a pit which is 11m away from the initial position.
total time T=24+5=29sec.
Answered by
1
Answer:
here is the answer
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Explanation:
8sec after that he is 2m away from an initial position
x= 5-3=2m in 8 sec
after 24sec he will 6m away from an initial position
He moves further 5m forward then he falls in a pit which is 11m away from the initial position.
total time T=24+5=29sec.
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