Physics, asked by sowmyasrimuthyala, 11 months ago

A drunkard is walking along a straight road. He takes 5 steps forward and 3 steps backward and so on. Each step is 1m long and takes 1s. There is a pit on the road 11 m away from the starting point. The drunkard will fall into the pit after how many seconds?

Answers

Answered by akankshayaduvanshi
0
I hope it will help you. . .

he will fall after 6 seconds
Answered by smruti74
0
5 steps - 3 steps = 2 steps
1 steps = 1m in 1s
The pit is 11m far from him /her
so, 11-3m=8m
as 1m takes 1s then 8m takes 8s
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