Question

A drunkard is walking along a straight road He takes 6 steps forward and 4steps backward and so on. Each step is 1m long and takes 1s. There is a pit 12m away. The drunkard will fall into the pit after

Answer 1

in 10sec net displacement of drunkyard is 2m

in 50 second drunkyard would have moved 10 m

in next 2 sec he falls in pit.. so in 52 sec he falls in pit

Answer 2

Answer:

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Distance covered with 1 step = 1 m

Time taken = 1 s

Time taken to move first 5 m forward = 5 s

Time taken to move 3 m backward = 3 s

Net distance covered = 5 – 3 = 2 m

Net time taken to cover 2 m = 8 s

Drunkard covers 2 m in 8 s.

Drunkard covered 4 m in 16 s.

Drunkard covered 6 m in 24 s.

Drunkard covered 8 m in 32 s.

In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.

Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s

I hope, this will help you

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Explanation: