A drunkard is walking on a straight road.He takes 5 steps forward and 3 steps backward and soon. Each step is 1 m long, and takes 1 s. There is a pit on the road 11 m away from starting point. The drunkard will fall into the pit
a) 21 s b) 29 s, c) 31 s, d) 37 s
Answers
For 8 total steps it takes 8 seconds, and moves in total 2 steps forward (2 m)
Therefore, 3*2 m = 6 m At 3rd cycle
Time Elapsed 24 s
After walking 5 m forward, he takes 5s more. It becomes 11 m.
Time = 24 + 5 = 29 S
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IndiankhiladiAce
Answer:
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Distance covered with 1 step = 1 m
Time taken = 1 s
Time taken to move first 5 m forward = 5 s
Time taken to move 3 m backward = 3 s
Net distance covered = 5 – 3 = 2 m
Net time taken to cover 2 m = 8 s
Drunkard covers 2 m in 8 s.
Drunkard covered 4 m in 16 s.
Drunkard covered 6 m in 24 s.
Drunkard covered 8 m in 32 s.
In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.
Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s
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