Math, asked by smithdestiny417, 1 year ago

A drunkard man moves 3 steps forward and than 1 step backward. In how many steps, he will fall in a
ditch which is 30 feet apart. Given that each step is 2 feet.

Answers

Answered by Gurbrahm
1

The Answer is 26 steps.

(Hint : He is only 15 steps away from the ditch and he covers each set of steps with a difference of 2).

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Answered by umasinghal604
0

Answer:

Step-by-step explanation:

if he is moving 3 steps forward and 1 step backward he is totally 4 steps but as he moves 3 steps forward he covers a distance of 6 feet but since he moves 1 step backward his total distance travelled becomes 4 feet. so this means that he covers 4 feet in 4 steps. so it actually means that he covers 1 feet in 1 step. so to fall in the ditch he has to move 30 steps as the ditch is 30 feet apart and then at 31st step he will fall down.

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