A drunkard man moves 3 steps forward and than 1 step backward. In how many steps, he will fall in a
ditch which is 30 feet apart. Given that each step is 2 feet.
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Answered by
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The Answer is 26 steps.
(Hint : He is only 15 steps away from the ditch and he covers each set of steps with a difference of 2).
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Answered by
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Answer:
Step-by-step explanation:
if he is moving 3 steps forward and 1 step backward he is totally 4 steps but as he moves 3 steps forward he covers a distance of 6 feet but since he moves 1 step backward his total distance travelled becomes 4 feet. so this means that he covers 4 feet in 4 steps. so it actually means that he covers 1 feet in 1 step. so to fall in the ditch he has to move 30 steps as the ditch is 30 feet apart and then at 31st step he will fall down.
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