Question

A drunkard moves on a straight road such that he takes 7 steps forward and 2 steps backward in each cycle. If the stride length of each step is 1 feet and the drunkard moves with a speed 2 feet/s in forward direction and 4 feet/s in backward direction, then the time after which the drunkard will fall into a pit 11 feet further from his starting point is

6 s

2.5 s

7s

2 s
​

Answer 1

Answer:

2.5 seconds is it ok haa lol