Question

A drunkard moves on a straight road such that he takes 7 steps forward and 2 steps backward in each cycle. If the stride length of each step is 1 feet and the drunkard moves with a speed 2 feet/s in forward direction and 4 feet/s in backward direction, then the time after which the drunkard will fall into a pit 11 feet further from his starting point is


6 s


2.5 s


7 s


2 s

Answer 1

Answer:

the correct answer is 7s

Answer 2

Answer:

7s

Explanation:

It'll take the drunkard 3.5s to travel 7 ft forward and 0.5 s to travel 2 ft backward. ( as per given data )

So accordingly he completes 5 ft in 4 s.

Now he has to travel the remaining 6 ft to fall in the pit.

Therefore, time taken by drunkard to travel 6 ft with velocity 2 ft/s will be 3 s.

Hence, total time required will be 4+3 = 7 s.

Good luck.