Question

a drunkard takes 3 leaps forward and 2 backward.each leap has a length of 1 foot.he stands at 20 feet from his houde and walks towards his home.what is the distance travelled by him and his displacement when he reaches home​

Answer 1

Explanation:

For every foot of forward distance traveled, he needs to take 5 leaps ( 3 forward 2 backward)

Hence to cover a distance of 20 feet he takes 20*5 = 100 leaps.

Distance is 100 ft

Displacement is 20ft

Answer 2

Answer:

The distance and the displacement are 100ft and 20ft.

Explanation:

Distance covered with 1 step = 1 m

Time taken = 1 s

Time is taken to move the first 3 m forward = 3 s

Time is taken to move 2 m backward = 2 s

Net distance covered = 3 - 2 = 1 m

Net time is taken to cover 1 m = 5s

he is standing 20 feet from his house and walks towards his home.

so, distance to cover: 20 × 5 = 100 ft.

and displacement is =20ft

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