Physics, asked by richa003priya, 1 year ago

A drunkard walking along a road takes 8 steps forward, 6 steps backward and so on. Each step is 1m long and of 1 sec. How much time will he take to fall in a pit 18m away?

Answers

Answered by overloadhunter05
0

the correct answer is 126sec


richa003priya: Ans is 78sec...but solution is also required
overloadhunter05: okay
overloadhunter05: i try
overloadhunter05: your answer correct but its is logical question
overloadhunter05: i cant this by witting
overloadhunter05: writing
Answered by Anonymous
2

Answer:Brainly.in

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indiankhiladi

Secondary School Physics 5+3 pts

A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backwards and so on. Each step is 1 metre long and requires 1 second. How long the drunkard takes to fall in a pit 13 metres away from the start

Report by Dharikumarndkm 29.07.2018

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Swigy

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Distance covered with 1 step = 1 m

Time taken = 1 s

Time taken to move first 5 m forward = 5 s

Time taken to move 3 m backward = 3 s

Net distance covered = 5 – 3 = 2 m

Net time taken to cover 2 m = 8 s

Drunkard covers 2 m in 8 s.

Drunkard covered 4 m in 16 s.

Drunkard covered 6 m in 24 s.

Drunkard covered 8 m in 32 s.

In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.

Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s

Explanation:

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