Question

a drunkard walking in a narrow Lane takes 5 step forward and three step backward followed again 5 step forward and 3 backwards on so each step is 1 metre long and required one second determine how long a drunkard take to fall in a pit13metre away from the start​

Answer 1

Explanation:

1m is covered in 1 sec

first 5m forward in 5 sec

then 3m backwards in 2sec

net distance travlled is 2m in time 8 seconds

so he will travel 8m in 32 secs

so for 13m only 5 m is left

after 8m he will travel 5m forward and will fall into pit... so no backward distance now n time for 5m is 5 sec

so total time will be 32 + 5 = 37 seconds

Answer 2

Answer:

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Distance covered with 1 step = 1 m

Time taken = 1 s

Time taken to move first 5 m forward = 5 s

Time taken to move 3 m backward = 3 s

Net distance covered = 5 – 3 = 2 m

Net time taken to cover 2 m = 8 s

Drunkard covers 2 m in 8 s.

Drunkard covered 4 m in 16 s.

Drunkard covered 6 m in 24 s.

Drunkard covered 8 m in 32 s.

In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.

Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s

I hope, this will help you

Explanation: