Question

A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward each stepl
of im long, per second & soon. Determine how long the drunkard takes to fall in a a pit 15m
away from the start.

Answer 1

15 m =10 m +5 m

The time taken to cover first 10 m=8*5=45 seconds

Time taken to cover last 5 m=5 seconds

Total time taken to cover 15 m =40 seconds + 5 seconds

                                                  =45 seconds                     (Ans)

Answer 2

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Distance covered with 1 step = 1 m

Time taken = 1 s

Time taken to move first 5 m forward = 5 s

Time taken to move 3 m backward = 3 s

Net distance covered = 5 – 3 = 2 m

Net time taken to cover 2 m = 8 s

Drunkard covers 2 m in 8 s.

Drunkard covered 4 m in 16 s.

Drunkard covered 6 m in 24 s.

Drunkard covered 8 m in 32 s.

In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.

Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s

I hope, this will help you

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