Question

A drunkard walking in a narrow lane takes 5 steps forward and 3 step backward,followed again by 5 steps forward and 3step backward,and so on. Each step is 1 m long and requires 1 s. Plot the x-tgraph of his motion. Determine graphically and otherwise how long the drunkard takes to fall in a pit 13 m away from the start.

Answer 1

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QUESTION:- A drunkard walking in a narrow lane takes 5 steps forward and 3 step backward,followed again by 5 steps forward and 3step backward,and so on. Each step is 1 m long and requires 1 s. Plot the x-tgraph of his motion. Determine graphically and otherwise how long the drunkard takes to fall in a pit 13 m away from the start.

ANSWER:- now we can write the given information

=> distance covered in 1 step=1m

=> time taken=1s

=> time taken to move first 5m forward =5s

=> time taken to move 3mbackwards=3s

=> here net distance covered =5-3=2cm

=> net time taken to cover 2m=8s

=> Drunkard covers 2m in 8 sec
=> drunkard covers 4m in 16 sec
=> drunkard covers 6m in 24 sec
=> drunkard covers 8m in 32 sec

In the net five sec step the drunkard will cover 5 m and total distance =13m
And the drunkard falls into the pit =13m

=>32+5=37 sec

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Answer 2

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Distance covered with 1 step = 1 m

Time taken = 1 s

Time taken to move first 5 m forward = 5 s

Time taken to move 3 m backward = 3 s

Net distance covered = 5 – 3 = 2 m

Net time taken to cover 2 m = 8 s

Drunkard covers 2 m in 8 s.

Drunkard covered 4 m in 16 s.

Drunkard covered 6 m in 24 s.

Drunkard covered 8 m in 32 s.

In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.

Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s

I hope, this will help you

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