Question

a drunkard walking on a narrow lane take three steps forward one step backward followed by three steps forward and one step back backward and so on. each step is 1 metre long and requires one second.. plot the x-t graph of his motion determine graphically that how long the drunkyard takes to fall in a pit 7 metre away from the start

Answer 1

Answer:

Brainly.in

What is your question?

indiankhiladi

Secondary School Physics 5+3 pts

A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backwards and so on. Each step is 1 metre long and requires 1 second. How long the drunkard takes to fall in a pit 13 metres away from the start

Report by Dharikumarndkm 29.07.2018

Answers

Brainly User

Hope this will help you

Click to let others know, how helpful is it

3.0

2 votes

THANKS 14

Report

Swigy

SwigyPhysics Newton

==============ⓢⓦⓘⓖⓨ

\huge\mathfrak\red{hello...frd\:swigy\:here}

==============ⓢⓦⓘⓖⓨ

Distance covered with 1 step = 1 m

Time taken = 1 s

Time taken to move first 5 m forward = 5 s

Time taken to move 3 m backward = 3 s

Net distance covered = 5 – 3 = 2 m

Net time taken to cover 2 m = 8 s

Drunkard covers 2 m in 8 s.

Drunkard covered 4 m in 16 s.

Drunkard covered 6 m in 24 s.

Drunkard covered 8 m in 32 s.

In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.

Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s

Explanation: