Question

A drunkard walks 5 steps forward and then 2 steps backward.Each step is 1 metre long and takes 1 second of time.How long it will take for him to fall in a pothole that is 15m away from where he started?​

Answer 1

5 step is equals to 5 metre
two step is equals to 2 meter
therefore 5 - 2 is equals to 3 metre
if the drunkyard continuous it 5 times he will fall into the pothole

Answer 2

Answer:

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Distance covered with 1 step = 1 m

Time taken = 1 s

Time taken to move first 5 m forward = 5 s

Time taken to move 3 m backward = 3 s

Net distance covered = 5 – 3 = 2 m

Net time taken to cover 2 m = 8 s

Drunkard covers 2 m in 8 s.

Drunkard covered 4 m in 16 s.

Drunkard covered 6 m in 24 s.

Drunkard covered 8 m in 32 s.

In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.

Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s

I hope, this will help you

Rea

Explanation: