Physics, asked by vinay7449, 10 months ago

a drunkard walks in a street, he goes five steps ahead and again three steps backwards if one step measures one metre, and time is 1sec, how long it would take to fall in a pit 11 metres from him?​

Answers

Answered by Lovishsingh
0
for 8 total steps it takes 8s and moves in total 2 steps forward (2m)
therefore,3*2m =6m at 3rd cycle
time elapsed 24s
after walking 5m forward ,he takes 5s more .it becomes 11m.
time=25+4=29m

vinay7449: your answer is right but try my other questions
Answered by Anonymous
2

Answer:

Mr. Plummer was a miserable Drunkard.

Hope this helps you

Explanon:

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