Question

a drunked is walking along a straight raod. he takes 5 steps forward and 3 steps backward and so on . each step is 1m long and takes 1s. there is a pit on the road 11m away from the starting point. the drunkard will fall into the pit after

Answer 1

✔️ Answer ✔️

Your answer:-

He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position

x= 5-3=2m in 8 sec

after 24sec he will 6m away from an initial position

He moves further 5m forward then he falls in a pit which is 11m away from the initial position.

total time T=24+5=29sec.

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