Question

A drunked walking in a narrow line takes 5 step forward & 3 steps backward each step of Im long, per
second and so on. Determine how long the drunked takes to fall in a pit 15m away from the start​

Answer 1

Answer:

each step= 1second

5step=5second

now drunked take 3 steps backward=5-3=2

time = 8 second

step. second

5. 5

2. 8

7. 13

4. 16

9. 21

6. 24

11. 29

8. 32

13. 37

and make a graph yourself

Answer 2

✔️ Answer ✔️

Your answer:-

He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position

x= 5-3=2m in 8 sec

after 24sec he will 6m away from an initial position

He moves further 5m forward then he falls in a pit which is 11m away from the initial position.

total time T=24+5=29sec.

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