A drunken person moves along a straight path such that person took 5 steps forward and
then 2 steps backward. Person follow this pattern for some time. If person covers 1 m
distance in each step and took 2 sec in each step then finda) Distance and displacement in 20 sec of motion.
b) If there is a pit hole at a distance of 16 m from starting point of motion then time taken
to fall in pit.
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Answer:
29 s
He moves 5 steps forward and 3 steps backward in 8sec after that he is 2m away from an initial position
x= 5-3=2m in 8 sec
after 24sec he will 6m away from an initial position
He moves further 5m forward then he falls in a pit which is 11m away from the initial position.
total time T=24+5=29sec.
Explanation:
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