Question

A dry cell can supply a charge of 300


c. if the current drawn from the cell is 60 ma find the time in which the cell completely discharged

Answer 1

Heya HERE is your answer

Q = 300
I = 60ma = 0.06A
T = Q/I
= 300/0.06
=5000
= 1.3 hr

Answer 2

Answer : t = 1.3 hours

Explanation :

It is given that,

Charge supply by a dry cell, q = 300 C

The current drawn by the cell, $I=60\ mA=60\times 10^{-3}\ A$

We know that the electric current is defined as total electric charge divided by time taken.

Mathematically, $I=\dfrac{q}{t}$

$t=\dfrac{q}{I}$

$t=\dfrac{300\ C}{60\times 10^{-3}\ A}$

$t=5000\ s$

$t=1.3\ hours$

The cell gets completely discharged in 1.3 hours.

Hence, this is the required solution.