a dry cell can supply a charge of 300 coulomb. If current drawn from cell is 600 mA find the time in which cell discharges.
Answers
Answered by
20
See there is a total amount of 300 C of charge in the battery.
Now current drawn in 600 mA which equals 0.6 A.
current means the amount of charge taken out in 1 second.
total charge = current * Time taken
time = 300/0.6 = 5000 s.
hope this helps
Now current drawn in 600 mA which equals 0.6 A.
current means the amount of charge taken out in 1 second.
total charge = current * Time taken
time = 300/0.6 = 5000 s.
hope this helps
Answered by
9
Answer
2×10^3 sec
Explanation:
Charge (Q)= 300C
Current ( I )=600mA => 600×10^-3A
time (t)= ?
W. K. T. ,
Q=It
t=Q/I
= 300/600×10^-3
= 2×10^3
The time is taken is 2×10^3.
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