Question

A dry soil sample weighing 100 g has volume of 60 ml and specific gravity 2.5. its void ratio is

Answer 1

the void ratio = 1/2

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Answer 2

$r_v=\frac{1}{3}$ is the void ratio.

Explanation:

Given:

• mass of dry soil, $m_s=100\ g$

• volume of dry soil, $V=60\ ml=0.06\ L=6\times 10^{-5}\ m^3$

• specific gravity of soil, $S=2.5$

Now the volume of the soil according to the given mass and specific gravity:

$V_s=\frac{m_s}{S\times 1000}$

$V_s=\frac{0.1}{2.5\times 1000}$

$V_s=4\times 10^{-5}\ m^3$

Now the void ratio:

$r_v=\frac{V-V_s}{V}$

$r_v=\frac{2\times 10^{-5}}{6\times 10^{-5}}$

$r_v=\frac{1}{3}$

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TOPIC: density, specific gravity

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