a duce is thrown 80 times. if the probability if having an even no. is 7/10 then how many times an odd no. appear on dice
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Answer:let s be the sample space
n(s) =80
let A be the event of getting even number
p(A) =n(A) /n(s)
7/10= n(A) /80
n(A) = 7/10*80
= 7*8
=56
let B be the event of getting odd number
n(B) = n(s) - n(A)
= 80 - 56
= 24
so, 24 times an odd number appears on dice
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