A dum bell of 10 kg mass falls from a height of 0.8m. What is the momentum transferred by the dum bell while hitting the ground.
Answers
Answered by
3
Yello,
The momentum transferred by the dum bell while hitting the ground is 3.17 Kgm/s. (approximately 3.2 Kgm/s)
Explanation in pic .
Hope you find my answer useful and hope you mark my answer as brainliest !
The momentum transferred by the dum bell while hitting the ground is 3.17 Kgm/s. (approximately 3.2 Kgm/s)
Explanation in pic .
Hope you find my answer useful and hope you mark my answer as brainliest !
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JunaidMirza:
Mass of object is 10 kg
Answered by
4
Velocity when it hits the ground is
v = √(2gH)
= √(2 × 10 m/s² × 0.8 m)
= 4 m/s
Momentum = Mass × Velocity
= 10 kg × 4 m/s
= 40 kgm/s
Momentum transferred by the dum bell is 40 kgm/s
v = √(2gH)
= √(2 × 10 m/s² × 0.8 m)
= 4 m/s
Momentum = Mass × Velocity
= 10 kg × 4 m/s
= 40 kgm/s
Momentum transferred by the dum bell is 40 kgm/s
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