Question

a
during the
A
Body moving
with
un forn acceleration
travels
distance of 24m and 64 m
tuo
equal consecutive
intervals of line,
each
duration
Determine the initial
velocity
acceleration of the moving body
first
4s.
of
and​

Answer 1

Answer:

let initial velocity u m/s and acceleration a m/s2 .

 

let distance travelled in first 4 s interval is S1, it is given by,  

begin mathsize 12px style S subscript 1 equals space u cross times t space plus 1 half cross times a cross times t squared space equals space 4 u plus 8 a space equals space 24 space........... left parenthesis 1 right parenthesis

end style

from (1), we get,   u+2×a = 6 .....................(2)

 

after 4 sec, velocity = u+a×t = u+4a

 

distance S2 travelled by second 4 s interval is given by

begin mathsize 12px style S subscript 2 space equals space open parentheses u plus 4 cross times a close parentheses cross times t space plus space 1 half cross times a cross times t squared space equals 4 u space plus space 24 a space equals 64 space............ left parenthesis 3 right parenthesis end style

from (3), we get u +6×a = 16 .......................(4)

By solving (2) and (4), we get u = 1 m/s , a = 2.5 m/s2

Explanation:

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