Question

a dynamometer D is attached to two blocks of masses 6kg and 4kg as shown in the figure. The reading of the dynamometer

Answer 1

Let x be the force recorded by dynamometer.

Both masses move in one direction.

The largest force is 20N and the least is 10 N.

This means x lies between 10 and 20.

This can be represented as shown.

10 < x < 20

The resultant force on :

6kg mass = 20 - x

4 kg mass = x - 10

They have equal acceleration as shown :

(20 - x) / 6 = (x - 10) / 4

4(20 - x) = 6( x - 10)

80 - 4x = 6x - 60

140 = 10x

x = 14 N

The acceleration is :

(20 - 14)/ 6 = 1 m/s²

Answer 2

For the mass of 6kg – 50 – D = 6a ….... (i) For the mass of 4kg – D – 30 = 4a ….....(ii) Solving (i) and (ii) we get a = 2m/s2 Putting the value of a in (ii) we get D – 30 = 4(2)=8

so D=38 N

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