a+e-ae=a = e(1-a). i need step by step explanation only
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Hey
Here's your answer !!
________
Now ,
a + e - ae = a ,
=> a + e - ae - a = 0
=> e - ae = 0
=> e ( 1 - a ) = 0 [ taking e common ] . [ proved ].
________
Hope it helps !!
Here's your answer !!
________
Now ,
a + e - ae = a ,
=> a + e - ae - a = 0
=> e - ae = 0
=> e ( 1 - a ) = 0 [ taking e common ] . [ proved ].
________
Hope it helps !!
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