Math, asked by sunnyyy7512, 10 months ago

A earns 10% more than B. By how much per cent is B's earning less than A.

Answers

Answered by dhriti48
0

Answer:

B earning is 9.09% less from A

Answered by mik37
1

Step-by-step explanation:

let B earning be 100 rupees

so A earning = 10%of 100 + 100

= 110 rupees

Therefore B's earning is 10 less than A's

so let the % less than be X

so x% of 110 should be equal to 10

= x÷100*110 = 10

= 11x÷ 10=10

= 11x = 100

= X = 100÷11

= X = 9.09 %

so B's earning is 9.09 % less than A's earning

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