Question

A earns 10% more than B. By how much percent is B's earnings less than A's earnings?

Answer 1

$\large{\underline { \sf{ \red{Given:- }}}}$

• A earns 10% more than B.

$\large{\underline { \sf{ \blue{To \: Find:- }}}}$

• By how much percent is B's earnings less than A's earnings?

$\large{\underline { \sf{ \orange{Directions:- }}}}$

$\mathrm \purple{Let:- }$

• The earnings of B be 100(for summing answer)

• Then, the earning of A is 110(10% more)

$\mathrm \purple{Now :-}$

$\leadsto \frac{(110 - 100)}{110} \times 100$

$\leadsto \frac{10}{110} \times \frac{100}{1}$

$\leadsto \frac{1000}{110}$

$\leadsto {9.09 \: percent}$

$\leadsto 9 \: percent$

$\large \pink{ \underline{ \sf{Therefore \: B's \: earnings \: is \: 9 \: percent \: less \: than \: A's. }}}$