Question

A earns 10% more then B. by how many percent is B earning less than A earnings?

Answer 1

Let the earnings of B be 100.

Given that A earns 10% more than B.

Then, the earning of A is 110.

Now

= > [(110 - 100)/110] * 100

= > (10/110) * 100

= > 1000/100

= > 9.09%

= > ~9%.

Hope it helps!

Answer 2

Lets B income is 100 then A’s income which is 10% more than B is 110.

Now , A’s income is 110, B’s income is 100,

Now percentage of B’s earning less than A is = difference of income/ A’s inome * 100 =110-100 / 110 * 100, = 10/110 * 100, =9.09 %