A.effective resistance of two 8 ohm resistors in the combination.
b.Current flowing through 4 ohm resistor.
c.Potential difference across 4 ohm resistance.
d. Power dissipated in 4 ohm resistor.
e.Difference in ammeter readings, if any.
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Effective resistance of two 8Ω resistors
(b) Current flowing through the circuit = current flowing through 4Ω
Equivalent resistance of the circuit = 4Ω + 4Ω = 8Ω
(c) Potential difference across 4Ω = V1 = IR1
= 1A x 4Ω = 4V
(d) Power dissipated in 4Ω = P = VI = 4V x 1A = 4 watt
(e) Both A1 and A2 show same reading because current remains same in series combination.
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e. ᴛʜᴇ ᴄᴜʀʀᴇɴᴛ ғʟᴏᴡɪɴɢ ᴛʜʀᴏᴜɢʜ ᴀ sᴇʀɪᴀʟʟʏ ᴄᴏɴɴᴇᴄᴛᴇᴅ ᴄɪʀᴄᴜɪᴛ, ʀᴇᴍᴀɪɴs ᴄᴏɴsᴛᴀɴᴛ ᴛʜʀᴏᴜɢʜᴏᴜᴛ ᴀɴᴅ sᴏ ᴛʜᴇʀᴇ ᴡɪʟʟ ɴᴏᴛ ʙᴇ ᴀɴʏ ᴄʜᴀɴɢᴇs ɪɴ ᴛʜᴇ ᴀᴍᴍᴇᴛᴇʀ ʀᴇᴀᴅɪɴɢ ɪʀʀᴇsᴘᴇᴄᴛɪᴠᴇ ᴏғ ᴛʜᴇ ᴘʟᴀᴄᴇ ᴡʜᴇʀᴇ ɪᴛ ɪs ᴄᴏɴɴᴇᴄᴛᴇᴅ. ᴡᴀs ᴛʜɪs ᴀɴsᴡᴇʀ ʜᴇʟᴘғᴜʟ?
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