Question

A electric dipole of dipole moment 2x10°c.m is placed in
an electric field of strength E = 4x10' N/c making an angle
30° with the field. Find the torque exerted on the dipoli.​

Answer 1

۞ Answer ۞

۞ Formula ۞

τ = PE sinθ

Here,

• τ is the torque

• P is the dipole

• E is the electric field strength

• θ is the angle between the electric field and dipole

۞ Given ۞

• Magnitude of dipole = 2 C.M

• Electric field strength = 4 x 1$0^{1}$ = 40 N/C

• Angle between the electric field and dipole = 30°

۞ Process ۞

Substituting the values, we get:

τ =2 x 40 x sin 30

  =80 x 0.5

  = 40 NM

★ Hence, torque exerted by dipole will be 40 NM ★

All the very best for your class 12th examination.

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