Question

(a) Electric fuse is an important component of all domestic circuits. Why?
(b) An electric oven of rating 2kW,220V is operated in a domestic circuit with a current rating of 5A. what result would you expect? Explain.

Answer 1

Ans: In this problem we have

Power of the oven (P) = 2 kW = 2000 W

Potential Difference (V) = 220 V

We have P = VI

⇒I=P/V

    = 2000/220

    = 9.09A


Here the current drawn by the electric oven is 9.09 A, which exceeds the safe limit of the circuit that is 5A. Therefore electric fuse will melt and break the circuit.

Answer 2

$\huge \bigstar \mathfrak{answer}$

P max = 2000 W

V = 220 V

I max = 5 A

P= VI

I= P/V

I=2000/220

I=100/11

I=9.09 A

Since the current is greater than the current rating( I max) the oven is going to short circuit.

BLAASSSSSSTTTTTTT.........(!o~o!)

FOLLOW ME

MARK BRAINLIEST