Question

A electron is moving with wavelength 590 nm.
Calculate potential with which the electron is
accelerated

Answer 1

Given:

A electron is moving with wavelength 590 nm.

To find:

Calculate potential with which the electron is  accelerated

Solution:

We use the formulae:

E = eV ...(1)

E = hν

⇒ E = hc/λ ...(2)

equating equations (1) and (2), we get,

eV = hc/λ

V = hc/eλ

From given, we have,

λ = 590 nm

V = [6.673 × 10^{-34} × 3 × 10^8] / [1.6 × 10^{-19} × 590 × 10^{-9}]

V = 2.0019 × 10^{-25} / 9.44 × 10^{-26}

V = 2.12 volts.

Therefore, the potential with which the electron is  accelerated is 2.12 V.