Question

A electron of mass m and charge e is accelerate by potential difference V it then enters a uniform magnetic field B applied perpendicular to it's path radius of circular path of it's electron is​

Answer 1

Answer:

hope u will understand

radius =

explanation

r=mv/qB

here,eV=1/2 mv²

2 eVm=(mv)²

mv=√2meV(sqrt is on whole term)

So,r=√2meV/eB

√(2mV/(√e)B