Question

a elevator descents into a mine shaft at the rate of 8m per minute if it decent starts from 20m about the ground level how long will it take to reach 340 m​

Answer 1

Answer:

Given :-

Speed of elevator = 8 m/minute

Initial height of elevator = 10 m

Final depth of elevator = -350 m

To Find :-

Time taken

Solution :-

Thus, distance to be descended by elevator = -350 + (-10 ) = -360 m

Time taken by elevator to descend -8 m = 1 minute

Time taken by the elevator to descend -360 m = -360 ÷ (-8)

= 40 minutes

Thus, time = 40 minutes

Answer 2

Answer:

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