Question

A elevator weighing 1500kg is to lift up at a constant velocity of 0.4m/s by a motor. Assume that fritional force oposses it's motion in motor.calculate the power of motor.

Answer 1

The force required to lift the elevator at a constant speed = its weight
= M * g = 1500 * 10 = 15,000 N

Power required = force* speed
P = 15,000 × 0.4 = 6,000 W

Answer 2

Power of motor = Fv
= mgv
= 1500 × 10 × 0.4
= 6000 W
= 6 kW

Power of motor is 6 kW