a energy of 6A flows in a resistor. how many coulombs of charge pass through the resistor in 2 minutes
Answers
Answered by
0
Explanation:
Current , i=
t
Q
or charge Q=it=5×(4×60)=1200C
Number of electrons n=
e
Q
=
1.6×10
−19
1200
=75×10
20
Answered by
10
Answer:
Given data:
- current (I) = 6A
- Time (t) = 2 minutes
= 2 × 60
= 120 seconds
Solution :
Coulombs = current (I) × time (t)
= 6 × 120
= 720 C
Explanation:
@GENIUS
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