Question

a equation kx(x-2√5)+10 find tha vakue if the k​

Answer 1

Step-by-step explanation:

refer to the attachment........

Answer 2

Answer:

kx(x – 2√5 ) + 10 = 0

⇒ kx² – 2√5 kx + 10 = 0

Here, a = k, b = – 2√5 k, c = 10

Given roots are equal,

★ D = b² – 4ac = 0

⇒ (–2√5 k)^2 – 4 × k × 10 = 0

⇒ 20k^2 – 40k = 0

⇒ 20k(k – 2) = 0

⇒ k(k – 2) = 0

⇒ k ≠ 0

⇒ k = 2