Question

A equilatual triangle whose length is 7.5m than find out it area

Answer 1

$\bf{\huge{\underline{\boxed{\sf\orange{Answer:3.75\sqrt {42.1875}m^2}}}}}$

Given :

• An equilateral triangle has length of 7.5 m

To Find :

• Area of the given equilateral triangle

$\huge\underline\green{\tt Solution:}$

→ Semi perimeter ( S )  

= $\dfrac{side_1 + side_2 + side_3}{2}$

= $\dfrac{7.5 + 7.5 + 7.5}{2}$

= $\dfrac{22.5}{2}$

= 11.25 m

→ Are of triangle

$=\sqrt{ s(s-side_1)(s - side_2)(s-side_3)}$

= $\sqrt{11.25(11.25-7.5)(11.25-7.5)(11.25-7.5)}$

= $\sqrt{11.25(3.75)(3.75)(3.75)}$

= $\sqrt{11.25\times 3.75\times 3.75\times 3.75}$

= $3.75 \sqrt{11.25\times3.75}$

Answer : = $3.75\sqrt{42.1875}\: m^2$