Math, asked by devilroy1990, 4 months ago

a. evaluate : (×¹/2y²/3 )where ×=9, y=8​

Answers

Answered by ritabanmaji
1

Answer:

x^1/2y^2/3

= (x^1 × 3)/2y^2

= (9^1 × 3)/2×8^2

=(9×3)/2×64

=(27)/128

=27/128.

Similar questions