Question

a.expand : (a+b) square

b.if the mean of 5,11,6,4,7,p and 10 is 8,find the value of p.

Answer 1

Answer:

a)  (a+b)² = a² + b² + 2ab

b) mean = sum of all observations/ total number of observations

         8      = 5+11+6+4+7+10+p/7    

         8      = 43 + p / 7

         8 × 7 = 43 + p

           56  = 43 + p

            56 - 43 = p

            13 = p      

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Answer 2

$\huge\bold{Solution}$


a) In this question we have to expand ${( a + b )}^{2}$....


Let expand this one by using identity....


${( a + b )}^{2}$


$\implies\bold{{a}^{2} + 2ab + {b}^{2}}$


b) $\underline{\bold{Given}}$


mean = 8.


$\underline{\bold{To\:Find}}$


Value of P.


$\underline{\bold{We\:know\:that}}$


$\boxed{\boxed{\bold{Mean = \dfrac{Sum\:of\:observation}{Number\:of\:observation}}}}$


$\underline{\bold{according\:to\:the\:question}}$


Add all the terms of LHS....


$\implies\bold{\dfrac{5 + 11 + 6 + 4 + 7 + P + 10}{7} = 8}$


$\implies\bold{\dfrac{43 + P}{7} = 8}$


shift 7 to RHS....


$\implies\bold{43 + P = 56}$

Shift 43 to RHS....


$\implies\bold{P = 56 - 43}$

Subtract 43 from 56....


$\implies\bold{13}$

The final answer is :

$\boxed{\boxed{\bold{\therefore{P = 13}}}}$